Too much 7 versus too much 8

Level 1

Find the value of 77777.....7777 7 repeated 2018 times 88888.....8888 8 repeated 2018 times \dfrac{\underbrace{77777.....7777}_{\text{7 repeated 2018 times}}}{\underbrace{88888.....8888}_{\text{8 repeated 2018 times}}}


The answer is 0.875.

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2 solutions

Jovan Boh Jo En
Feb 12, 2018

77777.....7777 7 repeated 2018 times 88888.....8888 8 repeated 2018 times \dfrac{\underbrace{77777.....7777}_{\text{7 repeated 2018 times}}}{\underbrace{88888.....8888}_{\text{8 repeated 2018 times}}} = 11111.....1111 1 repeated 2018 times × 7 11111.....1111 1 repeated 2018 times × 8 =\dfrac{\underbrace{11111.....1111}_{\text{1 repeated 2018 times}}\times 7}{\underbrace{11111.....1111}_{\text{1 repeated 2018 times}}\times 8} = 7 8 =\dfrac{7}{8} = 0.875 =\boxed{0.875}

Matin Naseri
Feb 12, 2018

77777.....7777 7 repeated 2018 times 88888.....8888 8 repeated 2018 times \dfrac{\underbrace{77777.....7777}_{\text{7 repeated 2018 times}}}{\underbrace{88888.....8888}_{\text{8 repeated 2018 times}}}

7 and 8 \text{7 and 8} both have same repeated

we can write this like below

7 8 \frac{7}{8} = 0.875 \boxed{0.875}

77 88 \frac{77}{88} = 0.875 \boxed{0.875}

777 888 \frac{777}{888} = 0.875 \boxed{0.875}

7777 8888 \frac{7777}{8888} = 0.875 \boxed{0.875}

77777.....7777 7 repeated 2018 times 88888.....8888 8 repeated 2018 times \dfrac{\underbrace{77777.....7777}_{\text{7 repeated 2018 times}}}{\underbrace{88888.....8888}_{\text{8 repeated 2018 times}}} = 0.875 \boxed{0.875}

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