How many of the following statements is/are true?
Any cyclic group is an abelian group.
Any simple abelian group is a cyclic group.
Let be a finite group, then the following are equivalent:
a) is prime.
b) and are the only subgroups in , and .
c) is a cyclic group and for some prime.
Relevant notes:
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a) A cyclic group G is a group generated by a single element. Let a ∈ G such that ⟨ a ⟩ = G , then ∀ b , c ∈ G , ∃ m , n ∈ Z such that b = a m and c = a n ⇒ b ⋅ c = a m ⋅ a n = a n ⋅ a m = c ⋅ b ⇒ G is an abelian group.
b) Each subgroup in an abelian group G is a normal subgroup,then if G is a simple abelian group and G = { e } , G is a cyclic group. If G = { e } , take a ∈ G with a = e . Then the subroup generated by a , thus ⟨ a ⟩ is a normal subgroup in G and ⟨ a ⟩ = { e } and being G a simple group, this implies that ⟨ a ⟩ = G , and therefore G is a cyclic group.
c)
c 1 ) ⇒ c 2 ) .- Apply Lagrange's theorem.
c 2 ) ⇒ c 3 ) .- If G is a finite group with { e } and G being the only subroups,we can take a = e since G = { e } and then ⟨ a ⟩ is a subgroup of G = { e } ⇒ ⟨ a ⟩ = G ⇒ G is a cyclic group and being G a finite group G ≅ Z p with p a prime (applying Lagrange's theorem again)
c 3 ) ⇒ c 1 ) .- Trivial