toooooooooooooooo easy ???? in fact not

Lets take the maximum of power of 4 in 37! as - A .
And lets take the product of powers of 13 in 169! as - B .
Find the value of (A+A+A+A+A+. . . . . . . . .)B times .

It is given that 37 is a prime number
and 169 is the square of 13


The answer is 0.

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1 solution

Rajdeep Dhingra
Feb 17, 2015

First let us evaluate B. B is given as the product of powers of 13 in 169!. That means the powers of 13 multiplied till the highest power which equals it or is less than 169!.

Powers of 13 are - 1 3 0 , 1 3 1 , 1 3 2 13^0 , 13^1 , 13^2

Due to presence of 0 we know the product will be 0. Hence B = 0 B = 0 .

Hence the ans ( A + A + A + A + ) × 0 = 0 (A + A + A+ A + \dots \dots) \times 0 = \boxed{0}

K.. Got it thanks.... Can You also post a solution for the second one...

Thanks for your help.

Mehul Arora - 6 years, 3 months ago

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Hopefully will do it in half an hour. Won't be online for long as today is my birthday.

Rajdeep Dhingra - 6 years, 3 months ago

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