Torque calculation

What is the torque of the force F = ( 2 i ^ 3 j ^ + 4 k ^ ) N \mathop F\limits^ \to = (2\hat i - 3\hat j + 4\hat k)N acting at the point r = ( 3 i ^ + 2 j ^ + 3 k ^ ) m \mathop r\limits^ \to = (3\hat i + 2\hat j + 3\hat k)\,m about the origin?

6 i ^ 6 j ^ + 12 k ^ 6\hat i - 6\hat j + 12\hat k 6 i ^ + 6 j ^ 12 k ^ - 6\hat i + 6\hat j - 12\hat k 17 i ^ + 6 j ^ + 13 k ^ - 17\hat i + 6\hat j + 13\hat k 17 i ^ 6 j ^ 13 k ^ 17\hat i - 6\hat j - 13\hat k

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1 solution

Tom Engelsman
Feb 28, 2016

thanks brother

pramesh guruung - 3 years, 9 months ago

Why wouldn't you be able to take F cross r? Shouldn't the negative as a result of crossing it the opposite way be just as viable of an answer?

Dylan Kruep - 3 years, 3 months ago

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It's a question I've wrangled with since my engineering undergrad years at Purdue, Dylan. I detest having to "cop-out", but r x F is the hidebound convention used in any statics/dynamics course in mechanical engineering + physics.

tom engelsman - 1 year, 5 months ago

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