Torque
The above shows a
m rod fixed by the rotation axis at the point where the internal division ratio is
If three forces indicated by the three red arrows--
N,
N, F--are acting and the rod does not rotate, what is the magnitude of
?
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Provided the rod does not rotate implies there is a momentum equilibrium among all the forces involved. Therefore, the equilibrium at the axis is the result of:
20N x sin(45) x its distance to axis + F x its distance to the axis - 40N x sin (45) x its distance to the axis.
20N x 2 / 2 x 1 + F x 2 = 40N x 2 / 2 x 2
10N x 2 + 2F = 40N x 2
2F = 30N x 2
F = 15N x 2 .