A car accelerates from rest at for seconds along a straight road. It then moves at a constant speed for It then decelerates uniformly to a stop in Find the total distance covered by the car.
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We can calculate the distance the car go in the first 20 seconds ( when it accelerates at 1 m/s2) : 200m. In the next 30 minutes, the car go straightly at the speed v= a times t. ( a stands for acceleration and t stands for the amount of time) . We got another 36000m. And then we figure out the distance of the last 30s when it decelerates: 300m Sum: 36500m