Total number of increasing functions

How many strictly increasing functions f f are possible such that f : A B f:A \rightarrow B , where A = { a 1 , a 2 , a 3 , a 4 , a 5 , a 6 } A=\{ a_1,a_2,a_3,a_4,a_5,a_6\} , and B = { 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 } B=\{ 1,2,3,4,5,6,7,8,9\} and a i + 1 > a i i N a_{i+1}>a_i \forall i \in \mathbb{N} and f ( a i ) i f( a_i) \neq i ?


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The answer is 28.

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1 solution

It is impossible that f ( a ) = 1 f(a)=1 , for any element in A A . Hence we need to only look to connect all the elements other than 1 1 . We now have ( 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 ) (2,3,4,5,6,7,8,9) . It can be observed that choosing a combination of any six numbers from this set will give us one and exactly one f f such that the conditions are satisfied. (make f f by choosing any 6 6 numbers and connecting them in ascending order from a 1 a1 to a 6 a6 )

Hence the answer is 8 c h o o s e 6 = 28 8 choose 6= \boxed{28}

How could you conclude that f ( a ) 1 f(a) \neq 1 . In the question, it's not given that f ( a i ) i f(a_{i}) \neq i .

Mathews Boban - 6 years, 2 months ago

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I also had same doubt

Avadhoot Sinkar - 5 years, 3 months ago

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Thanks. I have edited that f ( a i ) i f(a_i) \neq i . It used to be a i i a_i \neq i .

Calvin Lin Staff - 3 years, 3 months ago

Indeed ,, whats more beautiful is that only f(a1) not = 1 is needed along with the general increasing condition, the other possibilities of f(ai)=i is automatically blocked

Mvs Saketh - 6 years, 3 months ago

Can't the value of f ( a ) f(a) be same for 2 different values of a ? The function is increasing not strictly increasing.

Devang Agarwal - 5 years, 4 months ago

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Thanks. I have added that the function is strictly increasing.

Calvin Lin Staff - 3 years, 3 months ago

Over rated...

Rushikesh Joshi - 6 years, 2 months ago

How ??? f(ai) = i. Is a increasing function... It's it?? Should answer be 9 choose 6. 9C6.

Nivedit Jain - 3 years, 5 months ago

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