Total number of rational values

Algebra Level 4

How many rational values of a a exist for which the range of the function y = x 1 1 x 2 a y=\dfrac{x-1}{1-x^2-a} does not contain any value from the interval [ 1 , 1 ] [-1,1] .

Enter -1 as your answer if your answer comes out to be infinite.


The answer is 0.

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1 solution

Harsh Shrivastava
Feb 16, 2015

Putting x = 1 x = 1 , the value of y y comes out to be 0.

No matter what the value of a a be , at x = 1 x = 1 , value of y y will be zero and between [ 1 , 1 ] [-1,1] .

Hence there is no possible value of a a .

What about y y at a = 0 a=0 ?

Bhaskar Sukulbrahman - 6 years, 3 months ago

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It would be undefined if we put x = 1 x = 1 \implies value of y y will not exist.

Harsh Shrivastava - 6 years, 3 months ago

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When a = 0 a=0 , as x 1 x \rightarrow 1 , y 1 2 y \rightarrow \frac{-1}{2} . For all values of x > 1 x>1 , y ( 1 2 , 0 ) y \in (\frac{-1}{2}, 0) . So the answer should be 1 \boxed{1} since there exists only one value of a a that makes y y to lie in [ 1 , 1 ] [-1, 1] .

Bhaskar Sukulbrahman - 6 years, 3 months ago

at ( a = 0 ) y = x 1 1 x 2 y = x 1 ( x 1 ) ( x + 1 ) y = 1 x + 1 (a = 0) \Rightarrow y = \frac {x-1}{1-x^2} \Rightarrow y = \frac {x-1}{-(x-1)(x+1)} \Rightarrow y = -\frac {1}{x+1}

Putting ( x = 1 ) y = 1 2 [ 1 , 1 ] (x=1) \Rightarrow y = -\frac {1}{2} \in [-1,1]

Mustafa Embaby - 6 years, 3 months ago

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