....Touching New Heights.... (the correct one!!!)

Level pending

It was too late when Spiderman realised He has Lost his powers Of Making Nets.... He jumped from the top of a tower. The Height through which he falls in the first three seconds of his motion equals the height through which he falls in the last second of his motion. Let T be the Time taken for his total motion & H be the Height of tower. How much Is the value: (T + H) ?

Take time T in seconds and height H in meters & |g| = 10.0 .


The answer is 130.

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1 solution

Raj Error
Jan 6, 2014

T is the total time taken by him to reach the ground. Now, the height through he falls in first three seconds is ,say, h 1 h_{1} .

h 1 h_{1} = 1 2 \frac{1}{2} g t 2 t^{2} = 1 2 \frac{1}{2} * 10 * 3 2 3^{2} = 45 meters. The velocity of the stone 1 second before reaching the ground , i.e. at time ( T - 1 ) is v

v = g( T - 1 ) = 10( T - 1 ). This is the initial velocity for the last 1 second of the motion. During this 1 second, the stone will fall through a distance h 2 h_{2} given,

h 2 h_{2} = ut + 1 2 \frac{1}{2} g t 2 t^{2} = 10( T - 1 ) + 1 2 \frac{1}{2} * 10 * 1 2 1^{2} = 10( T - 1 ) + 5 = 10T - 5

Given h 1 h_{1} = h 2 h_{2}

45 = 10T - 5

T = 5 s e c o n d s \underline{T = 5 seconds}

Since T = 5s.

H = 1 2 \frac{1}{2} g t 2 t^{2} = 1 2 \frac{1}{2} * 10 * 5 2 5^{2}

Thus H = 125 m e t e r s \underline{H = 125 meters}

H + T = 125 + 5 = 130 \boxed{ 130 }

Sir, the answer to the last problem you added is not matching with this correct one!! why don't you please delete that one!! it's creating confusions!!

Neslihan Tursucu - 7 years, 5 months ago

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I couldn't!! Idon't know how to!! Can you teach me??

Raj Error - 7 years, 5 months ago

Thank You For this nice problem!

Sam Hansfield - 7 years, 5 months ago

I liked solving this problem. :)

Milly Choochoo - 7 years, 5 months ago

yeah!!! Right Neslihan!!

Panchu Patel - 7 years, 5 months ago

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