Integrate this: -sin^2(x)/cos(x) dx
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∫ cos x − sin 2 x d x = ∫ cos x − ( 1 − cos 2 x ) d x = ∫ cos x cos 2 x − 1 d x = ∫ ( cos x − cos x 1 ) d x = ∫ ( cos x − sec x ) d x
As you can see, the solution provided is not the integration result, but rather the other form of the integrant.
= ∫ ( cos x − sec x ) d x = ∫ cos x d x − ∫ sec x d x = sin x − ln ∣ tan x + sec x ∣ + c