A calculus problem by Nishant Rai

Calculus Level 3

I 1 = 1 3 ( x 2 + x + 3 ) f ( x 3 2 x 2 5 x + 2020 ) d x I 2 = 1 3 ( 4 x 2 3 x 2 ) f ( x 3 2 x 2 5 x + 2020 ) d x 2 I 1 3 I 2 = ? \begin{aligned} I_1 &=& \int _{ 1 }^{ 3 }{(x^2 + x + 3)f(x^3 - 2x^2 - 5x +2020)} \ dx \\ I_2 &=& \int _{ 1 }^{ 3 }{(4x^2 - 3x - 2)f(x^3 - 2x^2 - 5x +2020)} \ dx \\ \frac{2I_1}{3I_2} &=& \ ? \end{aligned}

To clarify: " ( a , b ) \in{(a,b)} " implies that your answer must be in between a a and b b exclusive.

( 1 , 0 ) \in{(-1,0)} ( 1 , 2 ) \in{(1,2)} ( 0 , 1 ) \in{(0,1)} ( 2 , 3 ) \in{(2,3)}

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1 solution

Nishant Rai
Apr 29, 2015

Which book is this

Rishabh Deep Singh - 5 years, 4 months ago

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Mathematics today

sagar kumar - 1 year, 6 months ago

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