Toughest Calculus ever in JEE.

Calculus Level 4

f ( x ) f(x) is a differentiable function and g ( x ) g(x) is a double differentiable function such that f ( x ) 1 | f(x) | \le 1 and f ( x ) = g ( x ) f'(x) = g (x) .

Let ( f ( 0 ) ) 2 + ( g ( 0 ) ) 2 = 9 \large\ { \left( f( 0) \right) }^{ 2 } + { \left( g( 0 ) \right) }^{ 2 } = 9 .

Then find AT LEAST how many c ( 3 , 3 ) c \in (-3, 3) exists satisfying

g ( c ) g ( c ) < 0 \large\ g (c) \cdot g''(c) < 0 .


The answer is 1.

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1 solution

Priyanshu Mishra
Aug 30, 2018

@Jon Haussmann , please post your solution.

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