Tower of 2016

Algebra Level 2

201 6 1 2 3 4 … 2016 = ? \Large 2016^{1^{2^{3^{4^{\dots^{2016}}}}}} = \, ?

Inspired by: Shubhang Mundra: Easy or easy


The answer is 2016.

Evan Huynh by Evan Huynh , 24, Sweden

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Rishabh Jain
Jan 9, 2016

1 raised to any power is one. Therefore 1 2 3 4 … 2016 = 1. Hence , 1^{2^{3^{4^{\dots^{2016}}}}} = 1. \space \text{Hence}, 2016 1 = 2016 \huge {2016}^1=2016

6 Helpful 0 Interesting 0 Brilliant 0 Confused

I had also posted a similar question but it had 2 instead of 2016 and the power tower was till 9.

Shubhang Mundra - 5 years, 5 months ago

Log in to reply

I have found your problem.

Evan Huynh - 5 years, 4 months ago

Log in to reply

Thanks,for adding a link

Shubhang Mundra - 5 years, 4 months ago
Akhash Raja Raam
Jun 13, 2016

Man I totally didn't see the trick and yet found the right answer! Now this is one good question!!!

0 Helpful 0 Interesting 0 Brilliant 0 Confused

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...