The number of ways can 14 identical toys be distributed among three boys , so that each gets at least one toy and no two boys get equal number of toys, is
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1,2,11 1,3,10 1,4,9 1,5,8 1,6,7
2,3,9 2,4,8 2,5,7
3,4,7 3,5,6
since the toys are identical each group can be formed only in 1 way, and since there are 10 groups and each group can be distributed in 3! ways so the answer comes out to be
3! x 10 = 60 qed:)