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Calculus Level 5

Find the length of the path traced by the function f ( x ) = x 2 + sin ( 4 x ) f(x)=\dfrac x2 +\sin (4x) in the interval [ 0 , π ] [0,\pi] . Write your answer to 3 decimal places.


The answer is 8.879.

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1 solution

The length of path of a function y = f ( x ) , x [ a , b ] y = f(x), x \in [a,b] is given by

L = a b 1 + ( d y d x ) 2 d x \large L = \color{#3D99F6}{\displaystyle \int_{a}^{b} \sqrt{1+ (\dfrac{dy}{dx})^2} dx}

y = f ( x ) = 1 2 + 4 cos 4 x y' = f'(x) = \frac{1}{2} + 4\cos 4x

Rest is trivial and the integral is left as an exercise to reader.

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