Consider the 2 -by- 2 matrix A = ( 5 − 1 1 3 ) . What is the trace of A 1 0 0 ?
Note:
The trace of a
2
-by-
2
matrix is defined as
Tr
(
a
c
b
d
)
=
a
+
d
.
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A little few calculations give us tr ( A ) = 2 3 , tr ( A 2 ) = 2 5 , tr ( A 3 ) = 2 7 ... So, if we define the trace sequence a n : = 2 n + 1 the question is to find a 1 0 0 .
A is similar to the matrix J which has a11=4 , a12=1, a21=0, a22=4. Letting P and P^-1 be the matrices of change of basis, A=PJP^-1. A^100=(PJP^-1)(PJP^-1)...=PJ^100P^-1 since PP^-1=Identity Matrix.
Diagonalization
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The eigenvalues of A are 4, 4, so that the eigenvalues of A 1 0 0 are 4 1 0 0 , 4 1 0 0 and the trace of A 1 0 0 is 2 × 4 1 0 0 = 2 2 0 1