Trailing zeros

Does there exist an integer k k such that k ! k! has more than k ÷ 4 k\div 4 trailing zeros?

There is none There are 2 There are many There is one

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Samuel Samuel
Jan 19, 2015

The max is k! Has the same number of trailing zeroes as k:4

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...