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1 solution
In a basic sequence the train can stop at Station 1, Station 3, Station 5, Station 7. So there are a minimum of 3 stations it has to skip, though the train can skip more as when it stops in this sequence Station1, Station 5, Station 9, Station 12.
So there are only 12 - 3 stops to choose from. So picking any 4 from the remaining 9 will yield the number of different ways a train can stop at 4 stations and also skipping consecutive stations. Hence the answer is 9C4 = 126