Train race!

Algebra Level pending

Two trains, one 350 350 feet long, the other 450 450 feet long, on parallel tracks, can pass each other completely in 8 8 seconds when moving in opposite directions. When moving in the same direction, the faster train completely passes the slower one in 16 16 seconds. Find the speed of the slower train in feet per second.


The answer is 25.

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1 solution

Let f f (feet per second) represent the speed of the faster train and s s (feet per second), the speed of the slower train. The relative speed when the trains are going in opposite directions is f + s f+s , and relative speed, when they are going in the same direction is f s f-s . In either case, the distance traveled is 350 + 450 = 800 350+450=800 (feet).

Since (relative) r a t e × t i m e = d i s t a n c e rate \times time = distance , we have ( f + s ) ( 8 ) = 800 (f+s)(8)=800 and ( f s ) ( 16 ) = 800 (f-s)(16)=800 . This pair of equations is easily solved, yielding the values f = 75 f=75 and s = 25 s=25 (feet per second).

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