Transformation on Inner Product Space

Algebra Level 2

Let V V be a real inner product space and there is a map T : V V T:V\rightarrow V which preserves the inner product, that is, for all vectors u u and v v in V V ,

u , v = T u , T v . \langle u,v\rangle =\langle Tu,Tv\rangle.

Must T T be linear map?

No Yes

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1 solution

Otto Bretscher
Oct 26, 2018

A straightforward but tedious computation shows that T ( a v + w ) a T ( v ) T ( w ) , T ( a v + w ) a T ( v ) T ( w ) = 0 \langle T(av+w)-aT(v)-T(w),T(av+w)-aT(v)-T(w)\rangle=0 for all vectors v , w v,w in V V and all scalars a a , by linearity in both arguments. Since the inner product is positive definite, it follows that T ( a v + w ) = a T ( v ) + T ( w ) T(av+w)=aT(v)+T(w) , meaning that T T is a linear map.

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