Transformer (8-13-2020)

A transformer is governed by the following equations:

E 1 = Z S I 1 + Z M I 2 E 2 = Z M I 1 + Z S I 2 E_1 = Z_S I_1 + Z_M I_2 \\ E_2 = Z_M I_1 + Z_S I_2

In the equations, E 1 E_1 and E 2 E_2 are the terminal voltages and I 1 I_1 and I 2 I_2 are the terminal currents (note the polarity conventions in the diagram). Z S Z_S and Z M Z_M are the transformer winding self and mutual impedances.

An AC voltage source with internal voltage E S E_S and internal impedance Z 1 Z_1 is connected across the first set of terminals, and an impedance Z 2 Z_2 is connected across the second set of terminals. Let Z 2 Z_2 be purely resistive ( Z 2 = R + j 0 ) (Z_2 = R + j 0) .

What is the limiting value of the magnitude of E 1 E_1 as R R approaches zero?

Bonus: What would the answer be if the transformer were ideal?

Details and Assumptions:
1) E S = 10 + j 0 E_S = 10 + j 0
2) Z 1 = 2 + j 5 Z_1 = 2 + j 5
3) Z S = 0 + j 10 Z_S = 0 + j 10
4) Z M = 0 + j 5 Z_M = 0 + j 5
5) Consider all quantities to be complex numbers. The quantity j j is the imaginary unit


The answer is 5.9246.

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1 solution

Talulah Riley
Aug 13, 2020

Nice problem
I have made the little changes in solving equation from last problem.
I am little bit confused about bonus, hope author will give its answer.

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