trapped between quadrants
Geometry
Level
2
Calculate area of the designed region in the fig common between the two quadrants of circles of radii 8 cm each.(Take Pi = 22/7)
265/14
256/7
236/14
236/7
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1 solution
Area ADCEA = Area ABCFA = 8 8 - (¼) (22/7) 8² = 96/7 cm² Area AECFA = (¼) (22/7)*8² - 96/7 = (256/7) cm²