Traveling Through A Neverending 'Fractional Fractions' Journey

Algebra Level pending

Given this 'infinitely long' fractional equation: 6 = A + 1 B + 1 C + 1 D + 1 E + … \sqrt{6} = A + \frac {1}{B + \frac {1}{C + \frac {1}{D + \frac {1}{E + \ldots}}}}

It is also given that the values of the consecutive variables A, B, C, ..., X, Y, and Z are positive integers.

Compute the value of: A + B + C + D + E + … + X + Y + Z A+B+C+D+E+\ldots+X+Y+Z


The answer is 76.

James R T by James R T , 21, Indonesia

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1 solution

Ankit Raghuwanshi
May 21, 2014

Since √6=2.44948... Therefore; A=2 Similarly; B=2 C=4 D=2 E=4 F=2 ...... Total comes out to be 76

1 Helpful 0 Interesting 0 Brilliant 0 Confused

Thnkx for your answer

Max B - 7 years ago

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