A calculus problem by Achal Jain

Calculus Level 2

Find an indefinite integral to 1 + x + x + x 2 x + 1 + x d x \color{#D61F06} \displaystyle \int { \frac { 1+x+\sqrt { x+{ x }^{ 2 } } }{ \sqrt { x } +\sqrt { 1+x } } } \, dx .


Clarification: C C denotes the arbitrary constant of integration .

2 ( 1 + x ) 3 2 + C 2(1+x)^{\dfrac{3}{2}} +C 2 ( 1 + x ) 3 2 3 + C \frac { 2{ (1+x) }^{ \dfrac { 3 }{ 2 } } }{ 3 } +C 1 1 + x 2 + C \frac { 1\sqrt { 1+x } }{ 2 } +C 1 + x + C \sqrt{1+x} +C

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Md Zuhair
Feb 27, 2017

Pretty simple... we can do it like this...

That's why the title. instead of substitution i just took the x common part outside the bracket from the numerator which lead to cancellation of denominator.

Achal Jain - 4 years, 3 months ago

Log in to reply

Ya sure it is always correct. But ibtaje a and b to make it easier

Md Zuhair - 4 years, 3 months ago

I did it by rationalising the polynomial.Your method is a much more simpler one.

Satwik Murarka - 4 years, 3 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...