Trial and Error

Algebra Level 2

If 3 x y = 9 x z = 12 y z = 1 3xy=9xz=12yz=1 , find x y z xyz .

±1/18 -1/18 None of these 1/18

Jayson Tipontipon by Jayson tipontipon , 22, Philippines

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

x y = 1 / 3 , x z = 1 / 9 , y z = 1 / 12 xy=1/3,xz=1/9,yz=1/12

( x y z ) 2 = 1 3 × 9 × 12 (xyz)^{2}=\frac{1}{3 \times 9 \times 12}

x y z = ± 1 18 xyz=±\frac{1}{18}

1 Helpful 0 Interesting 0 Brilliant 0 Confused

Thanks a lot for the solution dude. (Y)

Jayson tipontipon - 5 years, 6 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...