Triangle and Circles Basics

Level 2

Δ A B C \Delta ABC is a right angled triangle with A B = 3 c m AB = 3 cm . A circle is touching its sides A B AB and A C AC with centre O O and diameter B D BD . B D = 2 c m BD = 2 cm . Length of C D CD is m n \dfrac{m}{n} Give your answer as m 3 m 2 + n 3 n 2 m^3-m^2+n^3-n^2 . m , n m,n are co-prime


The answer is 48.

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1 solution

Marta Reece
Dec 21, 2017

t a n ( B A O ) = 1 3 tan(\angle BAO)=\frac13

E O C = B A C \angle EOC=\angle BAC

B A C = 2 × B A O \angle BAC=2\times \angle BAO

E C = t a n ( E O C ) = t a n ( 2 × B A O ) = 2 × t a n ( B A O ) 1 t a n 2 ( B A O ) = 2 3 1 1 9 = 3 4 EC=tan(\angle EOC)=tan(2\times \angle BAO)=\frac{2\times tan(\angle BAO)}{1-tan^2(\angle BAO)}=\frac{\frac23}{1-\frac19}=\frac34

O C 2 = O E 2 + E C 2 OC^2=OE^2+EC^2

O C 2 = 1 + 9 16 = 25 16 OC^2=1+\frac9{16}=\frac{25}{16}

D C = O C 1 = 5 4 1 = 1 4 DC=OC-1=\frac54-1=\frac14

m = 1 , n = 4 m=1, n=4

Answer = 1 1 + 64 16 = 48 =1-1+64-16=\boxed{48}

I really like the problem. I think it's elegant.

I feel that asking the solver to report the answer in a complicated form does not contribute to the overall effect, though.

Marta Reece - 3 years, 5 months ago

The problem is elegant if solved without any trigonometry.What are your views??

Sumukh Bansal - 3 years, 5 months ago

The answer is to be answered in a complicated form because if it is not so a person might get a trial-and-error correct answer.

Sumukh Bansal - 3 years, 5 months ago

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