Triangle angle problem

Geometry Level 3

Triangle A B C ABC is isosceles with B = C = 4 0 \angle B=\angle C=40^{\circ} and B C = 10 BC=10 . Extend A B AB to point D D so that A D = 10 AD=10 . Find A C D \angle ACD .


The answer is 50.

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1 solution

Julian Yu
Nov 26, 2018

Let E E be a point such that A D E \triangle ADE is equilateral (A and E are on opposite sides of BC). Triangles A B C , A C E ABC, ACE are congruent since A B = A C , B C = A D = A E , A B C = C A E = 4 0 . AB=AC, BC=AD=AE, \angle ABC=\angle CAE=40^\circ.

Thus A C = C E AC=CE and A D E C ADEC is a kite, so D C A E A C D = 5 0 DC \bot AE \Leftrightarrow \boxed{\angle ACD=50^\circ}

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