Triangle Area #1

Geometry Level 2

If the two side lengths of a triangle are given to be 15 and 11 cm, what is the maximum possible area of this triangle?


The answer is 82.5.

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1 solution

Since the formula of the area of a triangle is 1 2 a b S i n C \frac{1}{2}abSinC with 0 < S i n C 1 0 <\ Sin C\leq 1 . The maximum area occurs at Sin C is1

1 2 \frac{1}{2} * 15 11 1 = 82.5 _ 15*11*1=82.5\_\square

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