Triangle Drawn to a Circle

Geometry Level 2

Given circle Γ \Gamma , point A A is chosen outside of Γ \Gamma . Tangents A B AB and A C AC to Γ \Gamma are drawn. K K is a point on the circumference of Γ \Gamma contained within A B C ABC . D D is a point on A B AB and E E is a point on A C AC such that D K E DKE is a straight line and tangent to Γ \Gamma . If A B = 19 AB = 19 , what is the perimeter of triangle A D E ADE ?


The answer is 38.

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1 solution

Arron Kau Staff
May 13, 2014

Recall that the lengths of tangents from a point to a circle are equal. Since A B AB and A C AC are tangent to Γ \Gamma , we have A B = A C AB = AC . Similarly, D K = D B DK = DB and K E = E C KE = EC . Thus the perimeter of triangle A D E ADE is equal to A D + A E + D E = A D + A E + D K + K E = A D + A E + D B + E C = A B + A C = 2 A B = 2 × 19 = 38 \begin{aligned} AD + AE + DE &= AD + AE + DK + KE \\ &= AD + AE + DB + EC \\ &= AB + AC \\ &= 2AB \\ &= 2\times 19 \\ &= 38 \\ \end{aligned}

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