In any isosceles triangle ABC with vertex angle A equal to 20°,a cevian BD such that D lies on AC is constructed.Given angle CBD=60° and angle ABD=20°.Another cevian CE is constructed such that E lies on AB.Also given angle ACE=30° and angle BCE=50°.BD and CE intersect in F.Find the measure of angle FDE.
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Construct angle CBG=20° with G lying on AC and join GE.Proceed further and soon you'll get it done.