THE AREAS OF TWO SIMILAR TRIANGLES ARE IN THE RATIO OF 36:25.
Find the perimeter of the larger triangle, if the perimeter of the smaller is 125.
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yes.you r right.
How do you prove that the ration of their areas is r squared?
its not150 but180 because constant for solving36:25is not constant.
yes it must be 180
ratio of perimeter of two similar triangles is equal to the ratio of their sides and ratio of square of sides is equal to the ratio of areas.
thanks
Since the areas of triangles can be computed via 0.5 a b sin(c), it is clear to see that if the ratio of the areas is 36:25, the ratio of the sides would be 6:5. Hence, 125/5 6=150, the answer.
the ratio between the per and area is 0.5 so it is 6:5 so 125*6 divide 5=150
We can consider similar triangles as equilateral triangles of sides a and b (a>b). Given ratio of area of triangles as 36/25 therefore a 2/b 2=36/25 so a/b=6/5 so a=(6/5) b Therefore perimeter 3 a=3 (6/5) b=(6/5) (3 b)=(6/5) 125 (since 3 b=125 is perimeter of small triangle) Therefore perimeter of large triangle is =150
The ratio is 25:36. Therefore the perimeter has the same ratio. Supposing areas of triangles as 25x and 36x, we get perimeter as 180: 25x=125
x=5
So, 36x =perimeter=180
Did by the same way
yeah 180
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If the sides of two triangles have a ratio of r , then the ratio of their areas is r 2 .
Here, r 2 = 3 6 / 2 5 , so r = 6 / 5 . Then the perimeter of the larger triangle is 1 2 5 ⋅ 6 / 5 = 1 5 0 , not 180.