Triangle Tip

In a triangle $ABC$ , $x+y+2=0$ is the perpendicular bisector of side $AB$ and it meets AB at $(-1,-1)$ . If $x-y-1=0$ is the perpendicular bisector of side $AC$ and it meets $AC$ at $(2,1)$ and $P$ is the mid point of $BC$ then distance of $p$ from orthocentre of triangle $ABC$ is: