Triangles

Geometry Level 4

In a triangle A B C ABC , B A C = 1 5 \angle BAC=15^\circ and length A B AB is 10. Point D D is the point of intersection of the perpendicular bisectors of A B AB and B C BC . Given that length C D CD is 8, find the perimeter P P of the quadrilateral A B C D ABCD .

Input your answer as 1000 P \left\lfloor 1000P \right\rfloor .


The answer is 30141.

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2 solutions

Ahmad Saad
May 12, 2016

Usual notation DA=DB=DC=R=8. So extended Sin Law gives BC=2 * R * Sin15=4.141.
AB+BC+CD+DA=10+4.141+8+8=30.141.

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