Triangles

Geometry Level 2

In a right angled triangle One acute angle is double the other then the hypotenuse is

Double the smallest side Four times the smallest side Not affected Same as smallest side

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4 solutions

Daniel Lim
Apr 14, 2014

It is the 30-60-90 triangle with ratio 1 : 3 : 2 1:\sqrt{3}:2

but how do u prove this?

Divyanshu Vadehra - 6 years, 9 months ago
Ameya Salankar
Apr 5, 2014

Let the smallest acute angle be x x . Then,

9 0 + x + 2 x = 18 0 90^\circ + x + 2x = 180^\circ

Solving this, we get x = 3 0 x = 30^\circ .

This problem is the exact statement of 3 0 6 0 9 0 30^\circ - 60^\circ - 90^\circ theorem which states that if in a triangle, the angles are 3 0 , 6 0 , 30^\circ, 60^\circ, & 9 0 90^\circ , then the hypotenuse is twice the shortest side.

but how do u prove this?

Divyanshu Vadehra - 6 years, 9 months ago
. .
Feb 25, 2021

If we solve a simultaneous equation that is related to the angle of the right triangle, then we get x + y = 180 90 , x = 2 y x + y = 180 - 90, x = 2y .

Then, we get x = 60 , y = 30 x = 60, y = 30 .

This problem is related to trigonometric functions, but we do not have to know that.

If each angle of the triangle is 30 , 60 , 90 30, 60, 90 , then the length of the hypotenuse is double of its shortest side.

Then, the correct answer is Double the smallest side \boxed { \text { Double the smallest side } } .

PS: It is not the 'smallest'. In the geometrical works, we don't say 'the smallest' because the side cannot be the smallest. We say 'shortest' instead.

More exactly, sin 30 ° = 1 2 \displaystyle \sin 30\degree = \frac 12 , cos 30 ° = 3 2 \displaystyle \cos 30\degree = \frac { \sqrt3 } 2 , and tan 30 ° = 1 3 \displaystyle \tan 30\degree = \frac 1 { \sqrt3 } .

. . - 3 months ago

And sin 60 ° = 3 2 \displaystyle \sin 60\degree = \frac { \sqrt3 } 2 , cos 60 ° = 1 2 \displaystyle \cos 60\degree = \frac 12 , and tan 60 ° = 3 \displaystyle \tan 60\degree = \sqrt3 .

. . - 3 months ago
Nikko Quirap
Apr 12, 2014

Apply the 30-60-90 special right triangle

"the longer leg is square root of 3 times as long as the shorter leg while the hypotenuse is twice as long as the shorter leg"

but how do u prove this?

Divyanshu Vadehra - 6 years, 9 months ago

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