side BC represents 'a',
side AC represents 'b',
side AB represents 'c'.
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we have kbc = (b+c+a)(b+c-a) = b2+c2-a2+2bc hence k=( b2+c2-a2)/bc+2 = 2cosA+2 , if we maximize (2cosA+2 ) , the true answer for this problem is 4 i am sorry to say that ,the previous solution that k = 3 is wrong