Triangle's Perimeter

Geometry Level 3

If n n is a positive integer and n ! , ( n 2 ) ! , n ( 2 n ) ! n! , \ (n-2)!, \ \ n * (2-n)! are sides of a triangle, then what is its perimeter?


The answer is 5.

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1 solution

Maximos Stratis
Jun 12, 2017

For the ( n 2 ) ! (n-2)! to have meaning, it must be true that: n 2 2 n 2 n-2\geq 2\Rightarrow n\geq 2
For the ( 2 n ) ! (2-n)! to have meaning, it must be true that: 2 n 2 n 2 2-n\leq 2\Rightarrow n\leq2
Therefore: n = 2 n=2
So, the perimeter is:
P = n ! + ( n 2 ) ! + n ( 2 n ) ! = 2 ! + 0 ! + 2 0 ! = 2 + 1 + 2 = 5 P=n!+(n-2)!+n\cdot (2-n)!=2!+0!+2\cdot 0!=2+1+2=5


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