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Geometry Level 4

The no. of integral points (both the coordinates should be integers) that lie exactly in the interior of the triangles with vertices ( 0 , 0 ) , ( 0 , 21 ) , ( 21 , 0 ) \left( 0,0 \right) ,\left( 0,21 \right) ,\left( 21,0 \right) , is

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The answer is 190.

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1 solution

Since in 21 distances there are 21+1=22 lines. But two of them are on the boundaries. So inside there are only 20 lines in a 21x21 square.
So there will be 20x20=400 intersections. But for a triangle, the diagonal of the square is an additional boundary line robbing 20 intersections, 400-20=380.
Half of this will be in one triangle. So the no. of integral points = 380/2=190.

OR.

In the triangle we will have 3 boundaries. So interior intersections will be 22-3=19.
The top most line will have one, next 2, and so on. The last 19th line will have 19. So total= n ( n + 1 ) 2 = 19 ( 19 + 1 ) 2 = 190. \dfrac {n*(n+1)} 2=\dfrac {19*(19+1)} 2= \Large~~\color{#D61F06}{190}.

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