Triangular / Taxicab

Calculus Level 3

If n = 0 k = 1 5 k + 1 n + k ( k = 1 5 ( n + k ) ) 1 = T a + 1 Ta ( b ) 1 \sum_{n=0}^{\infty}\sum_{k=1}^5\frac{k+1}{n+k}\left(\prod_{k=1}^5(n+k)\right)^{-1}=\frac{T_{a}+1}{\text{Ta}(b)-1} where a , b a,b are positive integers and b b is prime , then find the value of a + b + 1 a+b+1 .

Notation : T m 0 , Ta ( n 1 ) T_{m\geq 0} ,\text{Ta}(n{\geq 1}) are mth triangular and nth Taxicab numbers respectively.

While entering your answer count T 0 = 0 T_0=0 as 1st triangular number.


Original problem


The answer is 19.

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