Tribonacci product

Algebra Level 2

What is the product of the first n n numbers in the Tribonacci sequence ?

n 3 + 3 n 2 3 \sqrt[3]{n^3 + 3n^2} 1 0 n 3 3 \frac{n^3}{3}

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4 solutions

Mahdi Raza
Jun 19, 2020

The Tribonacci sequence goes something like this: 0 , 1 , 1 , 0, 1, 1, \ldots . We see that the first term is 0 0 , hence the product of all the n n terms will also be 0 \boxed{0}

Did you look at Austin Li's problem? It's similar...

A Former Brilliant Member - 11 months, 3 weeks ago

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Yes @Yajat Shamji

Mahdi Raza - 11 months, 3 weeks ago
Srijan Singh
Jul 17, 2020

0 comes first

Yajat Shamji
Jul 1, 2020

0 × x = 0 0 \times x = \fbox 0 , no matter what x x is.

See this

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