Tribute to Euler

Calculus Level 4

If d d x ( d y d x ) = y \dfrac d{dx} \left( \dfrac {dy}{dx} \right) = \sqrt y , under the condition y = 1 y=1 , and d y d x = 2 3 \dfrac{dy}{dx} = \dfrac2{\sqrt3} at x = 0 x=0 , find y y when x = 2 3 x=2\sqrt3 .


The answer is 16.

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1 solution

Aayush Patni
Apr 2, 2016

Let y=f(x)

f''(x) = √(f(x)

Multiplying both sides of above equation by f'(x) and then integrating One gets

(f'(x)^2)/2 = 2/3 *(f(x)^3/2)

By using initial conditions one finds that the constant of integration=0

We have f'(x) = (2/√3)f(x)^3/4

dy/dx = (2/√3)y^3/4

Thus y^-3/4 dy = (2/√3) dx

Integrating both sides one gets

4y^1/4 =( 2/√3)*x + c

It is given that y=1 at x=0.

By putting the relation in above equation we get c=4

4y^1/4 = (2/√3)x + 4

Put x=2√3 to get y=16

hahahha it's just like you knew the text i took the question from

Benjamin ononogbu - 5 years, 2 months ago

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Nope. I definitely didn't. BTW from which book did u take this question???

Aayush Patni - 5 years, 2 months ago

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it's a text written by H.K DASS

Benjamin ononogbu - 5 years, 2 months ago

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