Trickonometry I

Geometry Level 3

sin θ = 6 + 2 4 \sin \theta = \dfrac {\sqrt 6 + \sqrt 2}4

Without using a calculator , which of the following values is a solution to θ \theta for the equation above?

Note: This Trigonometric Ratios Table may help.

Trickonometry II

11 5 115^\circ 9 5 95^\circ 8 5 85^\circ 12 0 120^\circ 10 5 105^\circ

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2 solutions

Ethan Mandelez
Apr 5, 2021

Recall the identity

sin ( A + B ) = sin A cos B + cos A sin B \sin (A+B) = \sin A \cos B + \cos A \sin B

Now, let's re-write the fraction to see whether we can rearrange it into that form.

6 + 2 4 = 6 4 + 2 4 \dfrac {\sqrt{6} + \sqrt{2}} {4} = \dfrac {\sqrt {6}} {4} + \dfrac {\sqrt {2}} {4}

= 3 2 × 2 2 + 1 2 × 2 2 = \dfrac {\sqrt{3}} {2} \times \dfrac {\sqrt{2}} {2} + \dfrac {1}{2} \times \dfrac {\sqrt{2}} {2}

Since this is equivalent to:

sin 60 cos 45 + cos 60 sin 45 \sin 60 \cos 45 + \cos 60 \sin 45

Therefore it is equal to sin ( 60 + 45 ) \sin (60+45) = sin 105 = \sin 105 .

If you haven't learnt Fundamental Trigonometric Identities and Specific Angles , I recommend to do so. They are very useful :D

Well I did it differently, the given value of sin = 0.96, so this immediately rules all options except sin(85) and sin(105). But since sin(85) = cos(5) and for 5 degree it said that cos will tend to 1 and 0.96 has a difference of 0.04 and 0.04 is huge in terms of approximation's. So the only possible answer is sin(105)

Omek K - 2 months, 1 week ago

you mean putting the options given in θ \theta ? That's another good approach to this question 👌

Ethan Mandelez - 2 months, 1 week ago

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Sorry I was editing. That's what I meant

Omek K - 2 months, 1 week ago

Yep, got it

Ethan Mandelez - 2 months, 1 week ago

sin θ = 6 + 2 4 = 3 2 2 2 + 1 2 2 2 = sin 6 0 cos 4 5 + cos 6 0 sin 4 5 = sin ( 6 0 + 4 5 ) = sin ( 10 5 ) θ = 10 5 \begin{aligned} \sin \theta & = \frac {\sqrt 6 + \sqrt 2}4 \\ & = \frac {\sqrt 3}2 \cdot \frac {\sqrt 2}2 + \frac 12 \cdot \frac {\sqrt 2}2 \\ & = \sin 60^\circ \cos 45^\circ + \cos 60^\circ \sin 45^\circ \\ & = \sin (60^\circ + 45^\circ) \\ & = \sin (105^\circ) \\ \implies \theta & = \boxed{105^\circ} \end{aligned}

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