Tricky algebraic problem
A railway line runs parallel to a road until a bend brings the road to a level crossing. Ahmed driving his car to work along the road every day at a constant speed of 30 m/h. He normally meets the train at the crossing. One day Ahmed was late by 6 minutes and met the train 5 miles ahead of the crossing. What is the speed of the train?
The answer is 75.
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1 solution
5 miles at 30m/h is 10 minutes. Ahmed was at meeting point 4 minutes before he was usually at dayly crossing. The train goes that distance of 5 miles in 1/15 of an hour, so its velocity is 5*15=75 m/h.