A and B are two points on a circle with a centre O and C lies outside the circle , on ray AB. If AB = 24 , BC =28 , OA = 15 then find OC.
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If you draw a perpendicular from O on AB, let foot of perpendicular be D, then by Pythagoras theorem AD= 9 cm and DC = 12+28= 40 cm and again by Pythagoras theorem CD= 41 cm