A truck accelerates up a 10° incline with a crate of 100 kg. Value of static coefficient of friction between the crate and the truck surface is 0.3. The maximum value of acceleration (in m/s2) of the truck such that the crate does not slide down is?
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Gravitation force component along the surface, Fg=100(9.8sin10)=170.2 N The maximum static friction= 0.3×100×9.8×cos10=289.5 N So ,the maximum force that can be exerted without causing acceleration is (289.5-170.2)N = 120 N So , the maximum acceleration is =120÷100 m/s^2 = 1.2 ms^-2