Tricky function

Algebra Level 3

The domain of the function f ( x ) = x sin ( ln x ) cos ( ln x ) f(x) = \frac{x}{\sqrt{\sin(\ln { x } ) - \cos(\ln { x } )}} is

( e ( 2 n + 1 4 ) π , e ( 3 n 3 4 ) π ) (e^{(2n+\frac{1}{4})\pi },e^{(3n-\frac{3}{4})\pi }) ( e ( 2 n + 1 4 ) π , e ( 2 n + 5 4 ) π ) (e^{(2n+\frac{1}{4})\pi },e^{(2n+\frac{5}{4})\pi }) ( e ( 2 n π , e ( 3 n + 1 2 ) π ) (e^{(2n\pi },e^{(3n+\frac{1}{2})\pi }) ( e ( 2 n + 1 2 ) π , e ( 2 n + 9 4 ) π ) (e^{(2n+\frac{1}{2})\pi },e^{(2n+\frac{9}{4})\pi })

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1 solution

Akhilesh Prasad
Sep 28, 2014

For the domain to be defined, the following conditions must satisfy

sin ( ln x ) > cos ( ln x ) \sin(\ln{x})>\cos(\ln{x}) and x > 0 x>0 ( \because The argument of a logarithm can not be negative)

Hence, 2 n π + π 4 < ln x < 2 n π + 5 π 4 2n\pi + \frac{\pi}{4}< \ln{x}< 2n\pi + \frac{5\pi}{4}

\Rightarrow e ( 2 n π + π 4 ) < x < e ( 2 n π + 5 π 4 ) e^{(2n\pi + \frac{\pi}{4})} < x < e^{(2n\pi + \frac{5\pi}{4})}

\therefore x ( e ( 2 n π + π 4 ) , e ( 2 n π + 5 π 4 ) ) x \in (e^{(2n\pi + \frac{\pi}{4})},e^{(2n\pi + \frac{5\pi}{4})})

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