Tricky Integral !

Calculus Level 2

if f(x) and g(x) are 2 real valued functions such that : f : R R f:R \rightarrow R g : R R g:R \rightarrow R

then the value of the integral : π / 2 π / 2 [ ( f ( x ) + f ( x ) ] [ g ( x ) g ( x ) ] d x = ? \int_{-\pi/2}^{\pi/2}[(f(x) + f(-x)][g(x) - g(-x)] dx = ?

π \pi 1 -1 0 0 π / 2 \pi/2

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1 solution

Aporajita Tume
Oct 13, 2014

as here is no specific function we consider the f(-x)=-f(x). and so there is nothing to integrate. so the ans is 0

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