[ lo g 1 0 ( tan ( 1 ∘ ) ) ] × [ lo g 1 0 ( tan ( 2 ∘ ) ) ] × [ lo g 1 0 ( tan ( 3 ∘ ) ) ] × ⋅ ⋅ ⋅ × [ lo g 1 0 ( tan ( 8 8 ∘ ) ) ] × [ lo g 1 0 ( tan ( 8 9 ∘ ) ) ] = ?
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also log(tanx)*log(tan(90-x))=0....for any x so,the ans must be zero...
Wait.. Tan(1) is the reciprocal of tan (89) so log(x) log(1/x) = log (x) log(-x) is not 0. I think only the first answer stands. C.
No, log(tanx)*log(tan(90-x)) = log(tanx + 1/tanx)...
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For every n = 1 , 2 , … , 8 9 , tan ( n ∘ ) > 0 hence lo g ( tan ( n ∘ ) ) is defined. Since lo g ( tan 4 5 ∘ ) = lo g ( 1 ) = 0 , the total product is also equal to 0 .