Tricky Logs

Geometry Level 1

[ log 10 ( tan ( 1 ) ) ] × [ log 10 ( tan ( 2 ) ) ] × [ log 10 ( tan ( 3 ) ) ] × × [ log 10 ( tan ( 8 8 ) ) ] × [ log 10 ( tan ( 8 9 ) ) ] = ? \left [ \log_{10} \left ( \tan \left ( 1^\circ \right ) \right ) \right ] \times \left [ \log_{10} \left ( \tan \left ( 2^\circ \right ) \right ) \right ] \times \left [ \log_{10} \left ( \tan \left ( 3^\circ \right ) \right ) \right ] \times \cdot \cdot \cdot \\ \times \left [ \log_{10} \left ( \tan \left ( 88^\circ \right ) \right ) \right ] \times \left [ \log_{10} \left ( \tan \left ( 89^\circ \right ) \right ) \right ] = \ ?


The answer is 0.

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2 solutions

Tijmen Veltman
Apr 8, 2015

For every n = 1 , 2 , , 89 n=1,2,\ldots,89 , tan ( n ) > 0 \tan(n^\circ)>0 hence log ( tan ( n ) ) \log(\tan(n^\circ)) is defined. Since log ( tan 4 5 ) = log ( 1 ) = 0 \log(\tan 45^\circ)=\log(1)=0 , the total product is also equal to 0 \boxed{0} .

also log(tanx)*log(tan(90-x))=0....for any x so,the ans must be zero...

Wait.. Tan(1) is the reciprocal of tan (89) so log(x) log(1/x) = log (x) log(-x) is not 0. I think only the first answer stands. C.

Chris Crawford - 5 years, 5 months ago

No, log(tanx)*log(tan(90-x)) = log(tanx + 1/tanx)...

Canwen Jiao - 3 years ago

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