Tricky mole

Chemistry Level 2

Find number of moles of water in a cylindrical tank having 1m radius and height of 7m.

Take (pi = {22}/7). Given water is assumed as pure water.

3.22 × 1 0 6 3.22 \times 10^6 1.44 × 1 0 6 1.44 \times 10^6 2.44 × 1 0 6 2.44 \times 10^6 1.22 × 1 0 6 1.22 \times 10^6

Adarsh Mahor by Adarsh Mahor , 21, India

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2 solutions

Volume of cylinder V = 22 m 3 = 22 , 000 L V =22 m^{3} = 22,000 L
Density of water D = 1 g m L = 1 k g L D = 1 \dfrac{g}{mL} = 1 \dfrac{kg}{L}
Mass of water W = D ⋅ V = 22 , 000 k g W = D\cdot V = 22,000 kg
Molecular weight of water M = 18 ⋅ 1 0 − 3 k g m o l M = 18 \cdot 10^{-3} \dfrac{kg}{mol}
Number of moles n = W M = 22 18 × 1 0 6 = 1.2222 × 1 0 6 n = \dfrac{W}{M} = \dfrac{22}{18} \times 10^{6} = 1.2222 \times 10^{6}
Question needs to be modified.

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Adarsh Mahor
Mar 8, 2016

Given water tank is cylindrical
So, volume of cylindrical= pi x r² x h
_ =22/7 x 1x1x7
= 22 m^3=22000 liters
_ _ _ _ _ Density= mass / volume
Density of water = mass/volume
( Density of water is 1000kg/m)
So, 1000= mass/22 x 10^3
Mass= 22x 10^6 grams
Mole = Given mass/molecular mass
Mole=(22x 10^6)/18( mass of water(H2O) is 18)
Mole = 1.2222 x 10^6

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Can you spot all your mistakes?

Calvin Lin Staff - 5 years, 3 months ago

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