Tricky Problem!

Algebra Level 4

Find The Interval Of a for which ax^2 + 2ax+1/2 is always positive for every real x .

give your answer as the number of integral values of a which satisfy the constraint.

0 infinitely many 2 many values of a are possible (but not infinite which are not given in the options) 3 1

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1 solution

Prakhar Bindal
Nov 4, 2015

The Problem Is Quite Simple But Is Tricky .

We Know That The Given Function Will Always Be Positive If Its Discriminant Is Less Than Zero and

coefficient of x^2 is greater than . Now Solving The Conditions We Get 0<a<1/2 .

So We Are Bound To Say That No Integral Value Exists .

But Wait ! . I Have No where said that the given function is a quadratic function hence a = 0 also . if a=0 then function for all x will have positive value .

Hence One Integral Value Of a exists .

Brilliant Problem!!!! :)

pankaj gupta - 5 years, 7 months ago

Its should be mentioned clear that the quadratic is not equated to zero.or else it does not make any sense(if equated to zero,how can we talk of positive values).so I guess it must be y=f(x).and then the set of x for which the constraint holds

Spandan Senapati - 4 years, 3 months ago

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Ohh well i didn't noticed it . i will edit it accordingly

Prakhar Bindal - 4 years, 3 months ago

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