Tricky trig -

Geometry Level pending

Find the value of the trigonometric expression

2 sin 2 ( 45 + θ ) sin 2 θ = 2\sin ^{ 2 }{ (45+\theta } )\quad -\quad \sin { 2\theta \quad =\quad }


The answer is 1.

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1 solution

Amos Noyun
Dec 15, 2014

sin a + cos a

= sin a + sin(90 - a)

= 2 sin(((90 - a) + a)/2) cos (((90 - a ) - a)/2) [Sum to Product formulas]

= 2 sin 45 cos(45 - a)

= 2 \sqrt{2} sin(90 - (45 - a)) = 2 \sqrt{2} sin(45 + a)

(sin a + cos a)^2 = 2 sin^2 (45+ a)

1 + sin 2*a = 2sin^2 (45 + a)

Therefore....

2sin^2 (45 + a) - sin 2* a = 1

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